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H?" c8X   4 4 4g"2j)" c   4 4 4" j>!B!j@!@!g"" "j&'j''f"" gxd02){\rtf1\ansi\deff0\deftab254{\fonttbl{\f0\fnil\fcharset0 Arial;}}{\pard\ql \x\fs20\b Question 3:\par \ql \x\fs20\b \par \ql \x\fs20 V\x\fs12\b R\x\fs20 = \par \ql \x\fs20 \par \ql \x\fs20 I\x\fs12\b R\x\fs20 = \par \ql \x\fs20 \par \ql \x\fs20 \par \ql \x\fs20 \par \ql \x\fs20 R1 = } }f"j10z"`/gR1350 - - -""b    `f"z"" H O   4 4 4""b   `z"" g"j""b   ``" g"dж0 /{\rtf1\ansi\deff0\deftab254{\fonttbl{\f0\fnil\fcharset0 Arial;}}{\pard\ql \x\fs20\b Question 1:\par \ql \x\fs20 .\par \ql \x\fs20 V\x\fs12\b R\x\fs20 = 7v\par \ql \x\fs20 \par \ql \x\fs20 I\x\fs12\b R\x\fs20 = 0.02A\par \ql \x\fs20 \par \ql \x\fs20 \par \ql \x\fs20 \par \ql \x\fs20 R1 = } } !x =xf"`10z"/gR1175   H? H?" b    `f"z"" 0 O  4 4 4"  B   @z"g"`"  b   `" " [h O  4 4 4" B~>b@~`@~@ @" "8H"  >b @ `" " B~b@~ @~` `" "Xh" ^b ``g"dYs){\rtf1\ansi\deff0\deftab254{\fonttbl{\f0\fnil\fcharset0 Arial;}}{\pard\ql \x\fs20\b Question 2:\par \ql \x\fs20\b \par \ql \x\fs20 V\x\fs12\b R\x\fs20 = \par \ql \x\fs20 \par \ql \x\fs20 I\x\fs12\b R\x\fs20 = \par \ql \x\fs20 \par \ql \x\fs20 \par \ql \x\fs20 \par \ql \x\fs20 R1 = } }dY7;{\rtf1\ansi\deff0\deftab254{\fonttbl{\f0\fnil\fcharset0 Arial;}}{\pard\ql \x\fs20 The next 3 circuits are a bit tricky - so think carefully about the voltages and apply principles you have learnt.\par \ql \x\fs20 Again, V\x\fs16 F\x\fs20 = 3 volts,\par \ql \x\fs20 \tab \tab I\x\fs16 F\x\fs20 = 20 mA} }d'{\rtf1\ansi\deff0\deftab254{\fonttbl{\f0\fnil\fcharset0 Arial;}}{\pard\ql \x\fs20\b Question 6:\par \ql \x\fs20 \par \ql \x\fs20 V\x\fs12\b R\x\fs20 = \par \ql \x\fs20 \par \ql \x\fs20 I\x\fs12\b R\x\fs20 = \par \ql \x\fs20 \par \ql \x\fs20 \par \ql \x\fs20 \par \ql \x\fs20 R1 = } } ggdжpK){\rtf1\ansi\deff0\deftab254{\fonttbl{\f0\fnil\fcharset0 Arial;}}{\pard\ql \x\fs20\b Question 4:\par \ql \x\fs20\b \par \ql \x\fs20 V\x\fs12\b R\x\fs20 = \par \ql \x\fs20 \par \ql \x\fs20 I\x\fs12\b R\x\fs20 = \par \ql \x\fs20 \par \ql \x\fs20 \par \ql \x\fs20 \par \ql \x\fs20 R1 = } } Pgd!V'{\rtf1\ansi\deff0\deftab254{\fonttbl{\f0\fnil\fcharset0 Arial;}}{\pard\ql \x\fs20\b Question 5:\par \ql \x\fs20 \par \ql \x\fs20 V\x\fs12\b R\x\fs20 = \par \ql \x\fs20 \par \ql \x\fs20 I\x\fs12\b R\x\fs20 = \par \ql \x\fs20 \par \ql \x\fs20 \par \ql \x\fs20 \par \ql \x\fs20 R1 = } } ppg"B!V r  V @!V @!r f"z"dpYV {\rtf1\ansi\deff0\deftab254{\fonttbl{\f0\fnil\fcharset0 Arial;}}{\pard\ql \x\fs20\b Question 8:\x\fs20 \par \ql \x\fs20 The circuit below needs a 450 ohm series resistor.} }de {\rtf1\ansi\deff0\deftab254{\fonttbl{\f0\fnil\fcharset0 Arial;}}{\pard\ql \x\fs20\b Question 7:\par \ql \x\fs20 Calculate the Power dissipated in the resistors of questions \x\fs20 2 & 3 in the spaces below. Remember to write down all the val\x\fs20 ues and your calculations.} }d p: m {\rtf1\ansi\deff0\deftab254{\fonttbl{\f0\fnil\fcharset0 Arial;}}{\pard\ql \x\fs20 The nearest \x\fs20\b\i preferred values\x\fs20 of the E12 resistor series are\par \ql \x\fs20\b 390\x\fs20 ohms or \x\fs20\b 470\x\fs20 ohms. \par \ql \x\fs20 \par \ql \x\fs20 Which one would you use and why?\par \ql \x\fs20 \par \ql \x\fs20 Value =\par \ql \x\fs20 \par \ql \x\fs20 Reason:} }d \V{\rtf1\ansi\deff0\deftab254{\fonttbl{\f0\fnil\fcharset0 Arial;}}{\pard\qc \x\fs32\b LED SERIES RESISTORS\par \ql \x\fs20 \par \ql \x\fs20 Answer the following questions by using Ohms Law to calculate\x\fs20 the required series resistance of R1 in each circuit.\par \ql \x\fs20 Remember to write down the voltages and currents and show the\x\fs20 calculations invloved.\par \ql \x\fs20 \par \ql \x\fs20 The LEDs used have the following parameters:\par \ql \x\fs20 \tab V\x\fs16 F\x\fs20 (Forward voltage) = 3 V\par \ql \x\fs20 \tab I\x\fs16 F\x\fs20 (Forward current) = 20 mA} }d ` & 5{\rtf1\ansi\deff0\deftab254{\fonttbl{\f0\fnil\fcharset0 Arial;}}{\pard\ql \x\fs20\b Q2/\par \ql \x\fs20\b \par \ql \x\fs20 V\x\fs12\b R\x\fs20\b =\par \ql \x\fs20\b \par \ql \x\fs20\b \x\fs20 I\x\fs12\b R\x\fs20\b = \par \ql \x\fs20\b \par \ql \x\fs20 P\x\fs12\b R\x\fs20\b =\par \ql \x\fs20\b } }d  4 5{\rtf1\ansi\deff0\deftab254{\fonttbl{\f0\fnil\fcharset0 Arial;}}{\pard\ql \x\fs20\b Q3/\par \ql \x\fs20\b \par \ql \x\fs20 V\x\fs12\b R\x\fs20\b =\par \ql \x\fs20\b \par \ql \x\fs20\b \x\fs20 I\x\fs12\b R\x\fs20\b = \par \ql \x\fs20\b \par \ql \x\fs20 P\x\fs12\b R\x\fs20\b =\par \ql \x\fs20\b } }d жV&  {\rtf1\ansi\deff0\deftab254{\fonttbl{\f0\fnil\fcharset0 Arial;}}{\pard\ql \x\fs20 Which is the most efficient method of lighting 2 LEDs and why?\par \ql \x\fs20\b \par \ql \x\fs20\b } }f" $`\)-5"^\x>!B!x@!`\@!"f""xq8H(">!B!~ 7 @! @!7 z""@ ?"@